tolong bantu jawab pakek cara kak
f'(x) = 2x² - 3x
f(1) = 1/6
[tex]\displaystyle\tt f(x) = \int f'(x) [/tex]
[tex]\displaystyle\tt f(x) = \int {2x}^{2} - 3x[/tex]
[tex]\displaystyle\tt f(x) = \frac{2}{2 + 1} {x}^{2 + 1} - \frac{3}{1 + 1} {x}^{1 + 1} + 1[/tex]
[tex]\displaystyle\tt f(x) =\frac{2}{3} {x}^{3} - \frac{3}{2} {x}^{2} + 1[/tex]
Jawaban B
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